Hotel De France, 29 rue des Minimes, 29250 Saint-Pol-de-Léon

Saint-Pol-de-Léon » De France Hotel
Hotel De France
29, rue des Minimes | 29250 Saint-Pol-de-Léon
29, rue des Minimes | 29250 Saint-Pol-de-Léon
Rate for double occupancy starts from € 65.00 (22 rooms total)
Find available rooms:
More information about Hotel De France, Saint-Pol-de-Léon:
Location map:
Hotel facilities:
Pets accepted |
Credit card accepted |
Park |
Free parking |
Bar |
Heating |
Mini bar |
Telephone |
Colour TV |
Congress facilities |




location details
Pets accepted